Which of the following correctly sets up the point-slope equation for this line?
yβ7=13(x+6)y-7=\frac{1}{3}\left ( x+6 \right )yβ7=
3
1
β
(x+6)
y+7=13(x+6)y+7=\frac{1}{3}(x+6)y+7=
3
1
β
(x+6)y+7=13(x+6)y+7=\frac{1}{3}(x+6)y+7=
3
1
β
(x+6)
y+7=13(xβ6)y+7=\frac{1}{3}(x-6)y+7=
3
1
β
(xβ6)
yβ7=13(xβ6)y-7=\frac{1}{3}(x-6)yβ7=
3
1
β
(xβ6)
