Answer:
When r1 ā r2 equal the wavelength of the monochromatic light
Explanation:
This is because to observe a bright fringe a constructive interference pattern of path difference, r1 ā r2 = mĪ» is observed, where m is an integer and Ī» = wavelength of monochromatic light.
For bright fringes and thus constructive interference, r1 ā r2 must be integral multiples of the wavelength, Ī». When r1 ā r2 , we have the central bright fringe and thus m = 0.
The first order bright fringe which is adjacent to the central bright fringe is obtained when m = 1,
So r1 ā r2 = 1 Ć Ī»
r1 ā r2 = Ī»
Thus, the path difference required to produce the first order bright fringe that is adjacent to the central bright fringe is when r1 ā r2 = Ī», the wavelength of the monochromatic light.