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A container initially holds 5.67 x 10^10-2 mol of propane and has a volume of V1. The volume of the container was increased by adding an additional 2.95 x 10^-2 mol of propane to the container, so that the container has a final volume of 1.93 L. If the temperature and pressure are constant, what was the initial volume of the container ,V1?

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jufsanabriasa

Answer:

The initial volume of the container was 1.27L

Explanation:

Avogadro's law states that under the same pressure and temperature, equal moles of gases occupies equal volume. The equation is:

Vā‚nā‚‚ = Vā‚‚nā‚

Where V is volume and n moles of 1, initial state and 2, final state.

In the problem, initial moles are 5.67x10ā»Ā², final moles after the addition are:

5.67x10ā»Ā² + 2.95x10ā»Ā² = 8.62x10ā»Ā² moles

And, after the addition, the volume is 1.93L.

Replacing in Avogadro's law:

Vā‚Ć—8.62x10ā»Ā² moles = 1.93LƗ5.67x10ā»Ā² moles

Vā‚ = 1.27L

The initial volume of the container was 1.27L

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