Moralesgilbert1420 Moralesgilbert1420
  • 04-06-2020
  • Mathematics
contestada

Find the perimeter of a rectangle with a length of 32 feet and a width of 56 feet

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gigibarton225
gigibarton225 gigibarton225
  • 04-06-2020

Answer:

Perimeter= 176

Step-by-step explanation:

If one length is 32, then the length parallel to it, is also 32. Meaning the side lengths altogether equal 64. The width, is 56, so then the width parallel to it is also 56. This means the width of each equals 112 altogether.

64+112=176.

P= 176 feet

Answer Link
TheAnimeGirl
TheAnimeGirl TheAnimeGirl
  • 04-06-2020

Hey!!!!

Here's your answer

Solution:

Length(l)=32 feet

Breadth(b)=56 feet

Now,

Perimeter of rectangle=2(l+b)

=2(32+56)

=2*88

=176

So the right answer is 176 feet

Hope it helps ...

Good luck on your assignment

Answer Link

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