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Two candles of equal height start to burn simultaneously. One of the candles is thicker than the other one and burns out in 4 hours, while the thinner one burns out in 2 hours. Both of the candles are extinguished after some time, and the remaining height of the thicker candle is now 3 times as long as the thinner one. How many minutes were the candles burning for?

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Answer:

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For 96 minutes the candles were burning if two candles of equal height start to burn simultaneously.  

What is the rate of change?

It is defined as the change in values of a dependent variable with respect to the independent variables.

W have:

Rate of burning for thicker = h/4

Rate of burning for thinner= h/2

remaining part = h - ht/4

remaining part = h - ht/2

h - ht/4 = 3(h - ht/2)

After solving for t:

t = 8/5 hours

or

t = 96 minutes

Thus, for 96 minutes the candles were burning if two candles of equal height start to burn simultaneously.  

Learn more about the rate of change here:

brainly.com/question/12786410

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