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Practice Problem #1: __TiO2 + __Cl2 + __C __TiCl4 + __CO2 + __CO

How many mol chlorine will react with 4.55 mol carbon?

What mass titanium (IV) oxide will react with 4.55 mol carbon?

How many molecules titanium (IV) chloride can be made from 115 g titanium (IV) oxide?

Respuesta :

Neetoo

Answer:

Explanation:

1)

Given data:

Moles of Clâ‚‚ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C  → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Clâ‚‚ with C.

                         C             :            Cl₂

                         3             :              4

                       4.55         :            4/3×4.55 = 6.1 mol

6.1 moles of chlorine will react with 4.55 moles of C.

2)

Given data:

Mass of TiOâ‚‚ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C  → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Clâ‚‚ with C.

                         C             :            TiO₂

                         3             :              2

                       4.55         :            2/3×4.55 = 3 mol

Mass of TiOâ‚‚:

Mass = number of moles × molar mass

Mass = 3 mol × 79.87 g/mol

Mass =  239.61 g

3)

Given data:

Molecules of TiClâ‚„ formed = ?

Moles of TiOâ‚‚ react = 115 g

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C  → 2TiCl₄ + CO₂ + 2CO

Number of moles of TiOâ‚‚:

Number of moles = mass/ molar mass

Number of moles = 115 g/ 79.87 g/mol

Number of moles = 1.44 mol

Now we will compare the moles of Clâ‚‚ with C.

                      TiO₂           :            TiCl₄

                         2             :              2

                       1.44           :            1.44

Molecules of TiClâ‚„:

1 mole = 6.022 × 10²³ molecules

1.44 ×6.022 × 10²³ molecules

8.672× 10²³ molecules

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