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The electric field strength is 20,000 N/C inside a parallel-plate capacitor with a 1.0 mm spacing. An electron is released from rest at the negative plate. What is the electronā€™s speed when it reaches the positive plate?

Respuesta :

The electronā€™s speed when it reaches the positive plate is 2.65 X 10ā¶m/s

Explanation:

Electric field strength, E = 20,000 N/C

Distance, x = 1 Ā mm = 1 X 10ā»Ā³m

Speed of the electron, s = ?

We know,

Charge of an electron, q = 1.602 X 10ā»Ā¹ā¹ C

So the force, F is

20000 N/C x Ā 1.602 X 10ā»Ā¹ā¹ C Ā = 3.2 X 10ā»Ā¹āµ Newtons

mass of electron is 9.1Ɨ10ā»Ā³Ā¹ kg

F = ma

a = 3.2 X 10ā»Ā¹āµ / 9.1 X 10ā»Ā³Ā¹ = 3.52 X 10Ā¹āµ m/sĀ²

v = āˆš(2ad) = āˆš(2*3.52 X 10Ā¹āµ X 0.001) = 2.65 X 10ā¶m/s

Therefore, the electronā€™s speed when it reaches the positive plate is 2.65 X 10ā¶m/s

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