maliyahcasey2 maliyahcasey2
  • 02-12-2019
  • Mathematics
contestada

Multiply the binomials (6a^3-5) (4a^3-11a)

Respuesta :

carlosego
carlosego carlosego
  • 09-12-2019

For this case we must multiply the following expression:

[tex](6a ^ 3-5) (4a ^ 3-11a) =[/tex]

We apply distributive property considering that:

[tex]+ * + = +\\+ * - = -\\- * - = +[/tex]

So:

[tex]6a ^ 3 * 4a ^ 3-6a ^ 3 * 11a-5 * 4a ^ 3 + 5 * 11a =[/tex]

To multiply powers of the same base, we place the same base and add the exponents.

[tex]24a^ {3 + 3} -66a^ {3 + 1} -20a ^ 3 + 55a =\\24a ^ 6-66a ^ 4-20a ^ 3 + 55a[/tex]

Answer:

[tex]24a ^ 6-66a ^ 4-20a ^ 3 + 55a[/tex]

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