adipalmer adipalmer
  • 01-11-2019
  • Mathematics
contestada

Show that in a quadrilateral ABCD, AB+BC+CD+DA<2(BD+AC)

Respuesta :

Rishi2005
Rishi2005 Rishi2005
  • 01-11-2019

Step-by-step explanation:

We know that the length of the diagonals will be more than the side.

Lets suppose the quadrilateral is a rectangle, with sides 6 and 4.

The length of a diagonal is:

√(6*6)+(4*4)

√36+16

√52

7.21(rounded off to 3 sig. fig.)

So, 6+4+6+4<2(7.21+7.21)

20< 2*14.42

20<28.84, which is true.

:)

Answer Link

Otras preguntas

What times what equals 15
What times what equals 15
What is 16x+9=9y−2x
40,583 in word format .......................................................... ......... .........
why did disputes over taxation figure so prominently in deteriorating relations between Britian and the colonies? between britain and the colonies ? please ref
What is the value of the digit 6 in the number 106,534
Convert 2.83 days into seconds
calculate the diameter of the circle r=2.7 m
Which important civil right is not granted to people living in U.S. territories? a. full Congressional representation b. electing local officials c. trial by
If it is 2:00 pm in Havana, Illinois, what time is it in Los, Angeles, California??