Answer:
The hydrostatic force of 313920 N is acted on each wall of the swimming pool and this force is acted at 1 m from the ground. The hydrostatic force is quadruple if the height of the walls is doubled.
Explanation:
To calculate force on the walls of swimming pool whose dimensions are given as 8-m-long, 8-m-wide, and 2-m-high. We know that formula for hydrostatic force is [tex]\text {hydrostatic force}=\text {pressure} \times \text {area,}=\rho g h \times(l \times h)[/tex] Â
[tex]\equiv \rho g h^{2} l[/tex], we know Ď=density of fluid=1000 [tex]g / c m^{3}[/tex],
g=acceleration due to gravity=9.81 [tex]m / s^{2}[/tex], h=height of the pool=2 m and l=length of the pool=8 m. Â
hydrostatic force on each wall=[tex]1000 \times 9.81 \times 2^{2} \times 8[/tex] = 313920 N.
The distance at which hydrostatic force is acted is half of the height of the swimming pool.
At 1 m from the ground this hydrostatic force is acted on each wall. Â
The force is quadruple if the height of the walls of the pool is doubled this is because, the height is doubled and taken as h=4 m and substitute in the equation =[tex]\rho g h^{2} l[/tex] = [tex]1000 \times 9.81 \times 4^{2} \times 8[/tex] = 1255680 N. This is 4 times 313920 N.
