At 2:15 PM, the temperature of a substance in a science experiment was 7βF. The temperature was then recorded at 15-minute intervals. At each interval, the new temperature was 3βF less than the previous temperature. Question 1 Part A Determine whether each expression could be used to find the temperature of the substance at 3:30 PM. Select Yes or No for each expression. (β3)(5) Yes Yes β (β3)(5) No No β (β3)(5) 7+(β3)(β5) Yes Yes β 7+(β3)(β5) No No β 7+(β3)(β5) 7+(β3)+(β3)+(β3)+(β3)+(β3) Yes Yes β 7+(β3)+(β3)+(β3)+(β3)+(β3) No No β 7+(β3)+(β3)+(β3)+(β3)+(β3) 7β(3)(5) Yes Yes β 7β(3)(5) No No β 7β(3)(5) 7+(5)(β3) Yes Yes β 7+(5)(β3) No No β 7+(5)(β3) Question 2 Part B What was the temperature of the substance at 3:30 PM?