At 2:15 PM, the temperature of a substance in a science experiment was 7∘F. The temperature was then recorded at 15-minute intervals. At each interval, the new temperature was 3∘F less than the previous temperature. Question 1 Part A Determine whether each expression could be used to find the temperature of the substance at 3:30 PM. Select Yes or No for each expression. (βˆ’3)(5) Yes Yes – (βˆ’3)(5) No No – (βˆ’3)(5) 7+(βˆ’3)(βˆ’5) Yes Yes – 7+(βˆ’3)(βˆ’5) No No – 7+(βˆ’3)(βˆ’5) 7+(βˆ’3)+(βˆ’3)+(βˆ’3)+(βˆ’3)+(βˆ’3) Yes Yes – 7+(βˆ’3)+(βˆ’3)+(βˆ’3)+(βˆ’3)+(βˆ’3) No No – 7+(βˆ’3)+(βˆ’3)+(βˆ’3)+(βˆ’3)+(βˆ’3) 7βˆ’(3)(5) Yes Yes – 7βˆ’(3)(5) No No – 7βˆ’(3)(5) 7+(5)(βˆ’3) Yes Yes – 7+(5)(βˆ’3) No No – 7+(5)(βˆ’3) Question 2 Part B What was the temperature of the substance at 3:30 PM?