The height of the javelin above the ground is symmetric about the line t = seconds. The javelin is 20 feet above the ground for the first time at t = seconds and again at t = seconds
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES. PLEASE SEE ATTACHED IMAGE. Part 1:
we must see in the graph the axis of symmetry of the given parabola. The axis of symmetry is the following vertical line: [tex] t = 2
[/tex] Answer: The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2: we must see the time t for which the javelin reaches a height of 20 feet for the first time. We have that when evaluating t = 1, the function is: [tex] h (1) = 20.
[/tex] To do this, just look at the graph. Then, we must observe the moment when it returns to be 20 feet above the ground. For this, we have from the graph that: [tex]h (3) = 20 feet
[/tex] Therefore, a height of 20 feet is again reached in 3 seconds. Answer: The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
